What is the extreme f(x,y)=(xy)/(sqrt(5x^2+2y^2+2xy+1)) ?

The extreme f(x,y)=(xy)/(sqrt(5x^2+2y^2+2xy+1)) is None

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extreme f(x,y)=(xy)/(sqrt(5x^2+2y^2+2xy+1))

extreme points

f (x, y) = \frac{x y}{5 x ^{2} + 2 y ^{2} + 2 x y + 1}

None

Solution steps

Find the critical points:

None

\frac{x y}{5 x ^{2} + 2 y ^{2} + 2 x y + 1}

has no critical points, therefore there are no extreme points

None

\frac{3 x}{x ^{2} - 9}

f (x, y) = 6 x^{2} - 8 y^{2}

f (x) = - x^{2} - 4 x - 3

f (x) = 4 x^{3} - 2 x^{2}

f (x) = (1 - cos (x))^{2}

What is the extreme f(x,y)=(xy)/(sqrt(5x^2+2y^2+2xy+1)) ?
The extreme f(x,y)=(xy)/(sqrt(5x^2+2y^2+2xy+1)) is None