What is the critical f(x)=40x-5x^2 ?

The critical f(x)=40x-5x^2 is x=4

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critical f(x)=40x-5x^2

critical points

f (x) = 40 x - 5 x^{2}

x = 4

Solution steps

40 x - 5 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4

Identify critical points not in

f (x)

domain

Domain of

40 x - 5 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 4

f (x) = 3 x^{\frac{2}{5}} - x^{\frac{3}{5}}

- x^{2} - 2 x + 8

y = 3 cos (x + \frac{π}{2}) + 1

(- 2.1) (4.7)

f (x) = lo g_{\frac{2}{5}} (x)