What is the extreme f(x)=(-x^2-6x-14)/(x+5) ?

The extreme f(x)=(-x^2-6x-14)/(x+5) is Minimum(-8,10),Maximum(-2,-2)

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extreme f(x)=(-x^2-6x-14)/(x+5)

extreme points

f (x) = \frac{- x ^{2} - 6 x - 14}{x + 5}

Minimum (- 8, 10), Maximum (- 2, - 2)

Solution steps

f^{'} (x) = \frac{- x ^{2} - 10 x - 16}{( x + 5 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 8,

Increasing

: - 8 < x < - 5,

Increasing

: - 5 < x < - 2,

Decreasing

: - 2 < x < \infty

Plug

x = - 8

into

\frac{- x ^{2} - 6 x - 14}{x + 5} : 10

Minimum (- 8, 10)

Plug

x = - 2

into

\frac{- x ^{2} - 6 x - 14}{x + 5} : - 2

Maximum (- 2, - 2)

Minimum (- 8, 10), Maximum (- 2, - 2)

f (x) = 17 + 4 x - x^{2}

y = 4 x^{2} + z^{2}

f (x, y) = - 4 x^{2} + 3 y^{2}

f (x) = x^{3} + 12 x^{2}

f (x y) = 2 x^{3} + y^{3} + 3 x^{2} - 3 y - 12 x - 4

What is the extreme f(x)=(-x^2-6x-14)/(x+5) ?
The extreme f(x)=(-x^2-6x-14)/(x+5) is Minimum(-8,10),Maximum(-2,-2)