What is the extreme f(x)=xsqrt(x+8) ?

The extreme f(x)=xsqrt(x+8) is Maximum(-8,0),Minimum(-16/3 ,-(32sqrt(2))/(3sqrt(3)))

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extreme f(x)=xsqrt(x+8)

extreme points

f (x) = x x + 8

Maximum (- 8, 0), Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

Solution steps

f^{'} (x) = \frac{3 x + 16}{2 x + 8}

Find intervals:

Decreasing

: - 8 < x < - \frac{16}{3},

Increasing

: - \frac{16}{3} < x < \infty

Plug

x = - 8

into

x x + 8 : 0

Maximum (- 8, 0)

Plug

x = - \frac{16}{3}

into

x x + 8 : - \frac{32 2}{3 3}

Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

Maximum (- 8, 0), Minimum (- \frac{16}{3}, - \frac{32 2}{3 3})

f (x) = \frac{x + 2}{x ^{2} - 3 x - 10}

f (x) = (x^{2} - 2 x) e^{- x}

y = \frac{1}{3} x^{3} - 9 x^{2} + 72 x + 2

f (x) = (2^{2} + 3 x)^{2} - (2 x^{3} - 4 y^{2})

x^{2} - 10 x

What is the extreme f(x)=xsqrt(x+8) ?
The extreme f(x)=xsqrt(x+8) is Maximum(-8,0),Minimum(-16/3 ,-(32sqrt(2))/(3sqrt(3)))