What is the extreme f(x,y)=x^3+2xy^2-(y^4)/x ?

The extreme f(x,y)=x^3+2xy^2-(y^4)/x is None

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extreme f(x,y)=x^3+2xy^2-(y^4)/x

extreme points

f (x, y) = x^{3} + 2 x y^{2} - \frac{y ^{4}}{x}

None

Solution steps

Find the critical points:

None

x^{3} + 2 x y^{2} - \frac{y ^{4}}{x}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{x ^{3}}{3 x ^{2} + 1}

9 x^{2} + 18 x + 7

f (x) = \frac{x - 3}{x ^{2}}

f (x) = x^{2} - 10 x - 5

x^{5} ln (x)

What is the extreme f(x,y)=x^3+2xy^2-(y^4)/x ?
The extreme f(x,y)=x^3+2xy^2-(y^4)/x is None