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Popular >

extreme y=2x^3-6x+1

Solution

extreme points

y = 2 x^{3} - 6 x + 1

Solution

Maximum (- 1, 5), Minimum (1, - 3)

Solution steps

f^{'} (x) = 6 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{3} - 6 x + 1 : 5

Maximum (- 1, 5)

Plug

x = 1

into

2 x^{3} - 6 x + 1 : - 3

Minimum (1, - 3)

Maximum (- 1, 5), Minimum (1, - 3)

Graph

Popular Examples

extreme f(x)=-9+x^2 extreme points

f (x) = - 9 + x^{2}

extreme f(x)=(-1)/(x-6)extreme points

f (x) = \frac{- 1}{x - 6}

extreme f(x,y)=x^3-18xy+y^3 extreme points

f (x, y) = x^{3} - 18 x y + y^{3}

extreme f(x)=x^4-3x^3+x^2 extreme points

f (x) = x^{4} - 3 x^{3} + x^{2}

extreme f(x)= 4/(x^2)extreme points

f (x) = \frac{4}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the extreme y=2x^3-6x+1 ?
The extreme y=2x^3-6x+1 is Maximum(-1,5),Minimum(1,-3)