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Popular >

extreme f(x)=1+2x-x^2

Solution

extreme points

f (x) = 1 + 2 x - x^{2}

Solution

Maximum (1, 2)

Solution steps

f^{'} (x) = - 2 x + 2

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 1

into

1 + 2 x - x^{2} : 2

Maximum (1, 2)

Graph

Popular Examples

extreme f(x,y)=6x^2-xy+4y^2 extreme points

f (x, y) = 6 x^{2} - x y + 4 y^{2}

extreme-x^4+4x^3+8x^2 extreme points

- x^{4} + 4 x^{3} + 8 x^{2}

extreme f(x,y)=3x^2-xy+5y^2 extreme points

f (x, y) = 3 x^{2} - x y + 5 y^{2}

extreme f(x)=x^{7/5}-12x^{1/5}extreme points

f (x) = x^{\frac{7}{5}} - 12 x^{\frac{1}{5}}

extreme f(x)=x^2-12 extreme points

f (x) = x^{2} - 12

Frequently Asked Questions (FAQ)

What is the extreme f(x)=1+2x-x^2 ?
The extreme f(x)=1+2x-x^2 is Maximum(1,2)