What is the extreme f(x)=2x^3-x^2-4x+4 ?

The extreme f(x)=2x^3-x^2-4x+4 is Maximum(-2/3 , 152/27),Minimum(1,1)

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extreme f(x)=2x^3-x^2-4x+4

extreme points

f (x) = 2 x^{3} - x^{2} - 4 x + 4

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

Solution steps

f^{'} (x) = 6 x^{2} - 2 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{2}{3}

into

2 x^{3} - x^{2} - 4 x + 4 : \frac{152}{27}

Maximum (- \frac{2}{3}, \frac{152}{27})

Plug

x = 1

into

2 x^{3} - x^{2} - 4 x + 4 : 1

Minimum (1, 1)

Maximum (- \frac{2}{3}, \frac{152}{27}), Minimum (1, 1)

f (x, y) = (2 x - x^{2}) (2 y - y^{2})

f (x) = (x - 2) e^{x} + 2

e^{7 x} + e^{- x}

f (x, y) = 2 + 2 x + 4 y - x^{2} - y^{2}

f (x) = x 81 - x^{2}

What is the extreme f(x)=2x^3-x^2-4x+4 ?
The extreme f(x)=2x^3-x^2-4x+4 is Maximum(-2/3 , 152/27),Minimum(1,1)