What is the extreme f(x,y)=x^2+2xy-(y^3)/x ?

The extreme f(x,y)=x^2+2xy-(y^3)/x is None

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extreme f(x,y)=x^2+2xy-(y^3)/x

extreme points

f (x, y) = x^{2} + 2 x y - \frac{y ^{3}}{x}

None

Solution steps

Find the critical points:

None

x^{2} + 2 x y - \frac{y ^{3}}{x}

has no critical points, therefore there are no extreme points

None

y = 3 x + 2 cos (x), 0 \leq x \leq 2 π

f (x) = 2 x - \frac{108}{x}

f (x, y) = x^{3} - y^{2} - 4 y + x^{2} y

f (x) = \frac{x}{x - 4}

f (x) = x^{2} + x y + y^{2} - 19 y + 120

What is the extreme f(x,y)=x^2+2xy-(y^3)/x ?
The extreme f(x,y)=x^2+2xy-(y^3)/x is None