What is the extreme f(x)=(x^2-2x+2)e^{1-x} ?

The extreme f(x)=(x^2-2x+2)e^{1-x} is Saddle(2, 2/e)

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extreme f(x)=(x^2-2x+2)e^{1-x}

extreme points

f (x) = (x^{2} - 2 x + 2) e^{1 - x}

Saddle (2, \frac{2}{e})

Solution steps

f^{'} (x) = - e^{1 - x} (x - 2)^{2}

Find intervals:

Decreasing

: - \infty < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

(x^{2} - 2 x + 2) e^{1 - x} : \frac{2}{e}

Saddle (2, \frac{2}{e})

y = \frac{x ^{3}}{- x ^{2} + 4}

4 x^{3} + 96 x^{2}

f (x) = x^{2} + 8 x + 15

(x - 2) (x^{2} - 4 x - 8)

f (x) = x^{3} + 2 x^{2} + x - 6

What is the extreme f(x)=(x^2-2x+2)e^{1-x} ?
The extreme f(x)=(x^2-2x+2)e^{1-x} is Saddle(2, 2/e)