What is the extreme f(x,y)=x^5+3x^3y^2+3xy^4 ?

The extreme f(x,y)=x^5+3x^3y^2+3xy^4 is None

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extreme f(x,y)=x^5+3x^3y^2+3xy^4

extreme points

f (x, y) = x^{5} + 3 x^{3} y^{2} + 3 x y^{4}

None

Solution steps

Find the critical points:

None

x^{5} + 3 x^{3} y^{2} + 3 x y^{4}

has no critical points, therefore there are no extreme points

None

f (x) = 3 x^{4} - 216 x^{2} - 5

f (x) = x (16 - 39 + 2 x) (\frac{39}{2} - x)

6 x - 7 x^{\frac{6}{7}}

f (x) = - x^{\frac{2}{3}} (x - 5), - 5 \leq x \leq 5

f (x, y) = \frac{x ^{3}}{3} - \frac{y ^{3}}{3} + 2 x y

What is the extreme f(x,y)=x^5+3x^3y^2+3xy^4 ?
The extreme f(x,y)=x^5+3x^3y^2+3xy^4 is None