What is the extreme f(t)=120-120h(t-2) ?

The extreme f(t)=120-120h(t-2) is Saddle(2,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(t)=120-120h(t-2)

extreme points

f (t) = 120 - 120 h (t - 2)

Saddle (2, 0)

Solution steps

Find the critical points:

(2, 0)

\frac{\partial ^{2} f}{\partial t ^{2}} = 0

D (t, h) = - 14400

Check the sign of at each critical point

Check critical point

(2, 0) :

Saddle

Saddle (2, 0)

f (x) = x^{6} (1 - x)^{18}

f (x) = x^{3} - x^{2} - x + 4, - 1 \leq x \leq 2

f (x, y) = - (x^{2} - y^{2}) e^{- x^{2} - y^{2}}

f (x) = x^{2} lo g_{2} (x)

f (x) = x (21 - 46 + 2 x) (\frac{46}{2} - x)

What is the extreme f(t)=120-120h(t-2) ?
The extreme f(t)=120-120h(t-2) is Saddle(2,0)