What is the extreme f(x,y)=-4x^2-2y^2-8x+12y+5 ?

The extreme f(x,y)=-4x^2-2y^2-8x+12y+5 is Maximum(-1,3)

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extreme f(x,y)=-4x^2-2y^2-8x+12y+5

extreme points

f (x, y) = - 4 x^{2} - 2 y^{2} - 8 x + 12 y + 5

Maximum (- 1, 3)

Solution steps

Find the critical points:

(- 1, 3)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 32

Check the sign of at each critical point

Check critical point

(- 1, 3) :

Maximum

Maximum (- 1, 3)

f (x, y) = \frac{4}{x + y}

f (x) = - x^{2} + 9, - 3 \leq x \leq 4

f (x) = x^{4} + y^{4} - 4 x y + 2

(7 x - 3)^{2}

f (x) = 20 x y - x^{3} - 10 y^{2}

What is the extreme f(x,y)=-4x^2-2y^2-8x+12y+5 ?
The extreme f(x,y)=-4x^2-2y^2-8x+12y+5 is Maximum(-1,3)