en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^2+12

Solution

extreme points

f (x) = - x^{2} + 12

Solution

Maximum (0, 12)

Solution steps

f^{'} (x) = - 2 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

- x^{2} + 12 : 12

Maximum (0, 12)

Graph

Popular Examples

extreme f(x)=(x^3)/(x-2)extreme points

f (x) = \frac{x ^{3}}{x - 2}

extreme f(x,y)=x^2+y^2-12x+16y extreme points

f (x, y) = x^{2} + y^{2} - 12 x + 16 y

extreme f(x)=14x+15x^{14/15}extreme points

f (x) = 14 x + 15 x^{\frac{14}{15}}

extreme f(x)=(x^3)/3+(15x^2)/2+50x-2 extreme points

f (x) = \frac{x ^{3}}{3} + \frac{15 x ^{2}}{2} + 50 x - 2

extreme y=x^{6/7}(x^2-4)extreme points

y = x^{\frac{6}{7}} (x^{2} - 4)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+12 ?
The extreme f(x)=-x^2+12 is Maximum(0,12)