What is the extreme f(x)=0.5x-6sqrt(x) ?

The extreme f(x)=0.5x-6sqrt(x) is Minimum(0,0),Minimum(36,-18)

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extreme f(x)=0.5x-6sqrt(x)

extreme points

f (x) = 0.5 x - 6 x

Minimum (0, 0), Minimum (36, - 18)

Solution steps

f^{'} (x) = 0.5 - \frac{3}{x}

Find intervals:

Increasing

: 0 \leq x < \frac{0.25}{9},

Decreasing

: \frac{0.25}{9} < x < \infty

Plug

x = 0

into

0.5 x - 6 x : 0

Minimum (0, 0)

Plug

x = 36

into

0.5 x - 6 x : - 18

Minimum (36, - 18)

Minimum (0, 0), Minimum (36, - 18)

f (x) = x^{4} - 12 x^{3} + 5

x 64 - x^{2}

f (x, y) = x \cdot e^{\frac{y}{x}}

f (x, y) = x y + 4

f (x) = x + 8 - x

What is the extreme f(x)=0.5x-6sqrt(x) ?
The extreme f(x)=0.5x-6sqrt(x) is Minimum(0,0),Minimum(36,-18)