What is the extreme f(x)=x^3+3x^2-9x+8 ?

The extreme f(x)=x^3+3x^2-9x+8 is Maximum(-3,35),Minimum(1,3)

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extreme f(x)=x^3+3x^2-9x+8

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 8

Maximum (- 3, 35), Minimum (1, 3)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 8 : 35

Maximum (- 3, 35)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 8 : 3

Minimum (1, 3)

Maximum (- 3, 35), Minimum (1, 3)

f (x) = x^{2} lo g_{5} (x)

f (x) = (x + 2)^{3} (x - 3)

f (x) = (x - 1) (x - 6)^{3} + 6, 1 \leq x \leq 4

f (x) = x^{4} - 5 x^{3} + x^{2} + 21 x - 18

f (x, y) = x^{2} - 2 x y + 2 y^{2} - 2 x + 2 y + 1

What is the extreme f(x)=x^3+3x^2-9x+8 ?
The extreme f(x)=x^3+3x^2-9x+8 is Maximum(-3,35),Minimum(1,3)