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Popular >

extreme 1/(sqrt(3-2x-x^2))

Solution

extreme points

\frac{1}{3 - 2 x - x ^{2}}

Solution

Minimum (- 1, \frac{1}{2})

Solution steps

f^{'} (x) = \frac{x + 1}{( - x ^{2} - 2 x + 3 ) ^{\frac{3}{2}}}

Find intervals:

Decreasing

: - 3 < x < - 1,

Increasing

: - 1 < x < 1

Plug

x = - 1

into

\frac{1}{3 - 2 x - x ^{2}} : \frac{1}{2}

Minimum (- 1, \frac{1}{2})

Popular Examples

extreme f(x)=xsqrt(x^2+36)extreme points

f (x) = x x^{2} + 36

extreme (-2x)/(x^2+y^2+1)extreme points

\frac{- 2 x}{x ^{2} + y ^{2} + 1}

extreme f(x)=x^2e^{16x}extreme points

f (x) = x^{2} e^{16 x}

extreme f(x)=3t^3+2t^2-10t+600 extreme points

f (x) = 3 t^{3} + 2 t^{2} - 10 t + 600

extreme 3x^2-x-2 extreme points

3 x^{2} - x - 2

Frequently Asked Questions (FAQ)

What is the extreme 1/(sqrt(3-2x-x^2)) ?
The extreme 1/(sqrt(3-2x-x^2)) is Minimum(-1, 1/2)