What is the extreme f(x)=-x^3+12x^2 ?

The extreme f(x)=-x^3+12x^2 is Minimum(0,0),Maximum(8,256)

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extreme f(x)=-x^3+12x^2

extreme points

f (x) = - x^{3} + 12 x^{2}

Minimum (0, 0), Maximum (8, 256)

Solution steps

f^{'} (x) = - 3 x^{2} + 24 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 8,

Decreasing

: 8 < x < \infty

Plug

x = 0

into

- x^{3} + 12 x^{2} : 0

Minimum (0, 0)

Plug

x = 8

into

- x^{3} + 12 x^{2} : 256

Maximum (8, 256)

Minimum (0, 0), Maximum (8, 256)

f (x) = 3 x + 2 y

e^{8 x} + e^{- x}

f (x) = x^{4} - x

f (x) = x^{2} + y^{2} + x y^{2}

f (t) = 10 e^{a t}

What is the extreme f(x)=-x^3+12x^2 ?
The extreme f(x)=-x^3+12x^2 is Minimum(0,0),Maximum(8,256)