What is the extreme f(x)=x^3-27x+5 ?

The extreme f(x)=x^3-27x+5 is Maximum(-3,59),Minimum(3,-49)

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extreme f(x)=x^3-27x+5

extreme points

f (x) = x^{3} - 27 x + 5

Maximum (- 3, 59), Minimum (3, - 49)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 5 : 59

Maximum (- 3, 59)

Plug

x = 3

into

x^{3} - 27 x + 5 : - 49

Minimum (3, - 49)

Maximum (- 3, 59), Minimum (3, - 49)

f (x) = 6 x + \frac{384}{x}

f (x) = - 2 x^{3} + 36 x^{2} - 192 x

f (x) = 2 x^{3} - 6 x^{2} - 144 x + 7

f (x) = - 3 + 3 x - x^{2}

f (x) = x (23 - 41 + 2 x) (\frac{41}{2} - x)

What is the extreme f(x)=x^3-27x+5 ?
The extreme f(x)=x^3-27x+5 is Maximum(-3,59),Minimum(3,-49)