What is the extreme f(x,y)= 1/(sqrt(x-y-4)) ?

The extreme f(x,y)= 1/(sqrt(x-y-4)) is None

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extreme f(x,y)= 1/(sqrt(x-y-4))

extreme points

f (x, y) = \frac{1}{x - y - 4}

None

Solution steps

Find the critical points:

None

\frac{1}{x - y - 4}

has no critical points, therefore there are no extreme points

None

f (x) = \frac{x ^{3}}{x ^{2} - 36}

f (x) = x^{3} - x^{4}

f (x) = 3 + x y - x - 2 y

f (x, y) = x^{3} - 3 x y

f (x) = (x - 1)^{3} + 2

What is the extreme f(x,y)= 1/(sqrt(x-y-4)) ?
The extreme f(x,y)= 1/(sqrt(x-y-4)) is None