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Popular >

extreme f(x)=4-5x+x^2

Solution

extreme points

f (x) = 4 - 5 x + x^{2}

Solution

Minimum (\frac{5}{2}, - \frac{9}{4})

Solution steps

f^{'} (x) = 2 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{2},

Increasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

4 - 5 x + x^{2} : - \frac{9}{4}

Minimum (\frac{5}{2}, - \frac{9}{4})

Popular Examples

extreme f(x,y)=x^2+xy+y^2-19y+120 extreme points

f (x, y) = x^{2} + x y + y^{2} - 19 y + 120

extreme f(x)=5-4x-x^3 extreme points

f (x) = 5 - 4 x - x^{3}

extreme f(x)=x^3+6x^2-5,-5<= x<= 2 extreme points

f (x) = x^{3} + 6 x^{2} - 5, - 5 \leq x \leq 2

extreme f(x)=x^3-6x^2+12x+2 extreme points

f (x) = x^{3} - 6 x^{2} + 12 x + 2

extreme f(x)=(-x^6-5x^3+5x)/(x^2+2)extreme points

f (x) = \frac{- x ^{6} - 5 x ^{3} + 5 x}{x ^{2} + 2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4-5x+x^2 ?
The extreme f(x)=4-5x+x^2 is Minimum(5/2 ,-9/4)