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Popular >

extreme f(x)=x^2+3x+5

Solution

extreme points

f (x) = x^{2} + 3 x + 5

Solution

Minimum (- \frac{3}{2}, \frac{11}{4})

Solution steps

f^{'} (x) = 2 x + 3

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

x^{2} + 3 x + 5 : \frac{11}{4}

Minimum (- \frac{3}{2}, \frac{11}{4})

Popular Examples

extreme f(x,y)= 1/3 sqrt(36-4x^2-9y^2)extreme points

f (x, y) = \frac{1}{3} 36 - 4 x^{2} - 9 y^{2}

extreme f(x)=0.2(x^4+4x^3-16x-16)+5 extreme points

f (x) = 0.2 (x^{4} + 4 x^{3} - 16 x - 16) + 5

extreme f(x)=(3x)/(x^2+2x-8)extreme points

f (x) = \frac{3 x}{x ^{2} + 2 x - 8}

extreme f(x)=-x^7ln(3x),(0,4)extreme points

f (x) = - x^{7} ln (3 x), (0, 4)

extreme (x^2)/(-x^2+4)extreme points

\frac{x ^{2}}{- x ^{2} + 4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+3x+5 ?
The extreme f(x)=x^2+3x+5 is Minimum(-3/2 , 11/4)