What is the extreme f(x)=x^3-5x^2-8x-8 ?

The extreme f(x)=x^3-5x^2-8x-8 is Maximum(-2/3 ,-140/27),Minimum(4,-56)

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extreme f(x)=x^3-5x^2-8x-8

extreme points

f (x) = x^{3} - 5 x^{2} - 8 x - 8

Maximum (- \frac{2}{3}, - \frac{140}{27}), Minimum (4, - 56)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x - 8 : - \frac{140}{27}

Maximum (- \frac{2}{3}, - \frac{140}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x - 8 : - 56

Minimum (4, - 56)

Maximum (- \frac{2}{3}, - \frac{140}{27}), Minimum (4, - 56)

f (x) = 9 x + 9 sin (x), 0 \leq x \leq 2 π

f (x) = x e^{- 4 x^{2}}

y = x^{\frac{2}{5}} (x + 3)

f (x) = x^{2} + x + 3

x + 2 cos (x)

What is the extreme f(x)=x^3-5x^2-8x-8 ?
The extreme f(x)=x^3-5x^2-8x-8 is Maximum(-2/3 ,-140/27),Minimum(4,-56)