What is the extreme f(x)=x^2-9,-4<= x<= 3 ?

The extreme f(x)=x^2-9,-4<= x<= 3 is Maximum(-4,7),Minimum(0,-9),Maximum(3,0)

Popular >

extreme f(x)=x^2-9,-4<= x<= 3

extreme points

f (x) = x^{2} - 9, - 4 \leq x \leq 3

Maximum (- 4, 7), Minimum (0, - 9), Maximum (3, 0)

Solution steps

Find the critical points:

x = - 4, x = 0, x = 3

Domain of

x^{2} - 9, - 4 \leq x \leq 3 : - 4 \leq x \leq 3

Find intervals:

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < 3

Plug the extreme point

x = - 4

into

x^{2} - 9 \Rightarrow y = 7

Maximum (- 4, 7)

Plug the extreme point

x = 0

into

x^{2} - 9 \Rightarrow y = - 9

Minimum (0, - 9)

Plug the extreme point

x = 3

into

x^{2} - 9 \Rightarrow y = 0

Maximum (3, 0)

Maximum (- 4, 7), Minimum (0, - 9), Maximum (3, 0)

f (x, y) = x^{2} y - 15 x y^{2} + 12 y

f (x, y) = 3 x^{2} y - 3 x^{2} - 3 y^{2} + y^{3} + 2

y = x^{3} - 3 x + 7

x^{4} - x^{3} - 6 x^{2}

f (x, y) = x^{2} + 2 y^{2} - x y

What is the extreme f(x)=x^2-9,-4<= x<= 3 ?
The extreme f(x)=x^2-9,-4<= x<= 3 is Maximum(-4,7),Minimum(0,-9),Maximum(3,0)