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Popular >

extreme f(x)=x^2-12x+8

Solution

extreme points

f (x) = x^{2} - 12 x + 8

Solution

Minimum (6, - 28)

Solution steps

f^{'} (x) = 2 x - 12

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 6

into

x^{2} - 12 x + 8 : - 28

Minimum (6, - 28)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-12x+8 ?
The extreme f(x)=x^2-12x+8 is Minimum(6,-28)