What is the extreme f(x)=-2/(x^2),0.5<= x<= 2 ?

The extreme f(x)=-2/(x^2),0.5<= x<= 2 is Minimum(0.5,-8),Maximum(2,-1/2)

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extreme f(x)=-2/(x^2),0.5<= x<= 2

extreme points

f (x) = - \frac{2}{x ^{2}}, 0.5 \leq x \leq 2

Minimum (0.5, - 8), Maximum (2, - \frac{1}{2})

Solution steps

Find the critical points:

x = 0.5, x = 2

Domain of

- \frac{2}{x ^{2}}, 0.5 \leq x \leq 2 : 0.5 \leq x \leq 2

Find intervals:

Increasing

: 0.5 < x < 2

Plug the extreme point

x = 0.5

into

- \frac{2}{x ^{2}} \Rightarrow y = - 8

Minimum (0.5, - 8)

Plug the extreme point

x = 2

into

- \frac{2}{x ^{2}} \Rightarrow y = - \frac{1}{2}

Maximum (2, - \frac{1}{2})

Minimum (0.5, - 8), Maximum (2, - \frac{1}{2})

f (x) = - \frac{2}{x ^{2}}, 0.5 \leq x \leq 5

f (x) = 2 - 3 x

x^{4} - 2 x^{2} - y^{2} + 3

f (t) = 9 cos (2 t)

S (X, Y) = X Y

What is the extreme f(x)=-2/(x^2),0.5<= x<= 2 ?
The extreme f(x)=-2/(x^2),0.5<= x<= 2 is Minimum(0.5,-8),Maximum(2,-1/2)