What is the extreme f(x)=x^3+3x^2-45x+6 ?

The extreme f(x)=x^3+3x^2-45x+6 is Maximum(-5,181),Minimum(3,-75)

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extreme f(x)=x^3+3x^2-45x+6

extreme points

f (x) = x^{3} + 3 x^{2} - 45 x + 6

Maximum (- 5, 181), Minimum (3, - 75)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 45

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 5

into

x^{3} + 3 x^{2} - 45 x + 6 : 181

Maximum (- 5, 181)

Plug

x = 3

into

x^{3} + 3 x^{2} - 45 x + 6 : - 75

Minimum (3, - 75)

Maximum (- 5, 181), Minimum (3, - 75)

- cos^{2} (x) - cos (x)

g (x, y) = 1 - (x + y)

f (x, y) = x^{2} + 3 y^{2} - 2 x y + 10 x - 2 y + 4

f (x) = x^{2} \cdot ln (x)

3 x^{\frac{2}{3}} - 2 x, - 1 \leq x \leq 1

What is the extreme f(x)=x^3+3x^2-45x+6 ?
The extreme f(x)=x^3+3x^2-45x+6 is Maximum(-5,181),Minimum(3,-75)