What is the extreme f(x)=x^3-4x^2-16x-1 ?

The extreme f(x)=x^3-4x^2-16x-1 is Maximum(-4/3 , 293/27),Minimum(4,-65)

Popular >

extreme f(x)=x^3-4x^2-16x-1

extreme points

f (x) = x^{3} - 4 x^{2} - 16 x - 1

Maximum (- \frac{4}{3}, \frac{293}{27}), Minimum (4, - 65)

Solution steps

f^{'} (x) = 3 x^{2} - 8 x - 16

Find intervals:

Increasing

: - \infty < x < - \frac{4}{3},

Decreasing

: - \frac{4}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{4}{3}

into

x^{3} - 4 x^{2} - 16 x - 1 : \frac{293}{27}

Maximum (- \frac{4}{3}, \frac{293}{27})

Plug

x = 4

into

x^{3} - 4 x^{2} - 16 x - 1 : - 65

Minimum (4, - 65)

Maximum (- \frac{4}{3}, \frac{293}{27}), Minimum (4, - 65)

f (x, y) = 400 - 49 x^{2} - 64 y^{2}

f (x) = 2 x ln ∣ x ∣

f (x, y) = x^{2} + y^{2} - 2 x

f (x) = x^{3} + 8

f (x) = \frac{900}{x} + 2 π x^{2}

What is the extreme f(x)=x^3-4x^2-16x-1 ?
The extreme f(x)=x^3-4x^2-16x-1 is Maximum(-4/3 , 293/27),Minimum(4,-65)