What is the extreme f(x)=x^2(x^2-4) ?

The extreme f(x)=x^2(x^2-4) is Minimum(-sqrt(2),-4),Maximum(0,0),Minimum(sqrt(2),-4)

Popular >

extreme f(x)=x^2(x^2-4)

extreme points

f (x) = x^{2} (x^{2} - 4)

Minimum (- 2, - 4), Maximum (0, 0), Minimum (2, - 4)

Solution steps

f^{'} (x) = 4 x (x + 2) (x - 2)

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{2} (x^{2} - 4) : - 4

Minimum (- 2, - 4)

Plug

x = 0

into

x^{2} (x^{2} - 4) : 0

Maximum (0, 0)

Plug

x = 2

into

x^{2} (x^{2} - 4) : - 4

Minimum (2, - 4)

Minimum (- 2, - 4), Maximum (0, 0), Minimum (2, - 4)

f (x, y) = ln (36 - 4 x^{2} - 9 y^{2})

f (x) = \frac{1}{3} x^{3} - x^{2} + 3

f (x) = \frac{1}{3} x^{3} - x^{2} + 1

(x + 2)^{2} (x - 3)

f (x) = 3 cos (2 x) + 4

What is the extreme f(x)=x^2(x^2-4) ?
The extreme f(x)=x^2(x^2-4) is Minimum(-sqrt(2),-4),Maximum(0,0),Minimum(sqrt(2),-4)