What is the extreme f(x)=7sec(x) ?

The extreme f(x)=7sec(x) is Minimum(2pin,7),Maximum(pi+2pin,-7)

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extreme f(x)=7sec(x)

extreme points

f (x) = 7 sec (x)

Minimum (2 πn, 7), Maximum (π + 2 πn, - 7)

Solution steps

Find the critical points:

x = 2 πn, x = π + 2 πn

Domain of

7 sec (x) : 2 πn \leq x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Find intervals:

Increasing

: 2 πn < x < \frac{π}{2} + 2 πn,

Increasing

: \frac{π}{2} + 2 πn < x < π + 2 πn,

Decreasing

: π + 2 πn < x < \frac{3 π}{2} + 2 πn,

Decreasing

: \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Plug the extreme point

x = 2 πn

into

7 sec (x) \Rightarrow y = 7

Minimum (2 πn, 7)

Plug the extreme point

x = π + 2 πn

into

7 sec (x) \Rightarrow y = - 7

Maximum (π + 2 πn, - 7)

Minimum (2 πn, 7), Maximum (π + 2 πn, - 7)

f (x) = x^{7} (x + 4)^{4}

f (x) = - x e^{- \frac{x}{2}}

x 36 - x

\frac{( x ^{2} - 8 )}{x - 3}

f (x y) = x^{2} + 2 x^{2} - x y + 14 y

What is the extreme f(x)=7sec(x) ?
The extreme f(x)=7sec(x) is Minimum(2pin,7),Maximum(pi+2pin,-7)