What is the range of xsqrt(x-1) ?

The range of xsqrt(x-1) is f(x)>= 0

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range of xsqrt(x-1)

range

x x - 1

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x x - 1 : x \geq 1

Extreme Points of

x x - 1 :

Minimum

(1, 0)

Find the range for the interval

1 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0

f (x) = x \cdot (x + 1)

16 y^{2} - 9 x^{2} = 144

f (x) = \frac{9}{3 - 10 x}

\frac{1}{5} x^{5} + x^{4} + x^{3}

f (x) = \frac{x ^{2} + 5}{3 x ^{2} - 14 x - 5}