What is the extreme f(x,y)=8x^2-4y^2 ?

The extreme f(x,y)=8x^2-4y^2 is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=8x^2-4y^2

extreme points

f (x, y) = 8 x^{2} - 4 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = - 128

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

(5 - 9 t)^{\frac{9}{2}}

f (x) = 5 x^{2} ln (4 x)

f (x) = x + y + x^{2} y + x y^{2}

x^{3} - 48 x y + 64 y^{3}

f (x, y) = 2 x^{3} + 3 x^{3} y^{2} - 4 x^{2} y^{2} - 2 y

What is the extreme f(x,y)=8x^2-4y^2 ?
The extreme f(x,y)=8x^2-4y^2 is Saddle(0,0)