What is the extreme f(x,y)=-2.8+x^2-6.4xy+1.4y^2 ?

The extreme f(x,y)=-2.8+x^2-6.4xy+1.4y^2 is Saddle(0,0)

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extreme f(x,y)=-2.8+x^2-6.4xy+1.4y^2

extreme points

f (x, y) = - 2.8 + x^{2} - 6.4 x y + 1.4 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2.8

D (x, y) = - 35.36

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x, y) = 4 x y + x^{4} + y^{4}

- x^{2} + 5

\frac{5 x - 6}{x}

\frac{d}{d x} ((x^{2} - 4) (y^{2} - 9))

9 x^{8} + 1

What is the extreme f(x,y)=-2.8+x^2-6.4xy+1.4y^2 ?
The extreme f(x,y)=-2.8+x^2-6.4xy+1.4y^2 is Saddle(0,0)