en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2x^2+2x

Solution

extreme points

f (x) = - 2 x^{2} + 2 x

Solution

Maximum (\frac{1}{2}, \frac{1}{2})

Solution steps

f^{'} (x) = - 4 x + 2

Find intervals:

Increasing

: - \infty < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

- 2 x^{2} + 2 x : \frac{1}{2}

Maximum (\frac{1}{2}, \frac{1}{2})

Graph

Popular Examples

extreme g(x,y)=\sqrt[3]{x^2+y^2-9}extreme points

g (x, y) = 3 x^{2} + y^{2} - 9

extreme f(x)=2500x-5x^2+10000 extreme points

f (x) = 2500 x - 5 x^{2} + 10000

extreme f(x)=(10-2x)(10-2x)(x)extreme points

f (x) = (10 - 2 x) (10 - 2 x) (x)

extreme 2x^2-3x+5 extreme points

2 x^{2} - 3 x + 5

extreme f(x)=(x-1)^2(x+3)^2 extreme points

f (x) = (x - 1)^{2} (x + 3)^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2+2x ?
The extreme f(x)=-2x^2+2x is Maximum(1/2 , 1/2)