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Popular >

extreme y=x^2-7x-4

Solution

extreme points

y = x^{2} - 7 x - 4

Solution

Minimum (\frac{7}{2}, - \frac{65}{4})

Solution steps

f^{'} (x) = 2 x - 7

Find intervals:

Decreasing

: - \infty < x < \frac{7}{2},

Increasing

: \frac{7}{2} < x < \infty

Plug

x = \frac{7}{2}

into

x^{2} - 7 x - 4 : - \frac{65}{4}

Minimum (\frac{7}{2}, - \frac{65}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2-7x-4 ?
The extreme y=x^2-7x-4 is Minimum(7/2 ,-65/4)