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Popular >

extreme y=-2x^2-3x+1

Solution

extreme points

y = - 2 x^{2} - 3 x + 1

Solution

Maximum (- \frac{3}{4}, \frac{17}{8})

Solution steps

f^{'} (x) = - 4 x - 3

Find intervals:

Increasing

: - \infty < x < - \frac{3}{4},

Decreasing

: - \frac{3}{4} < x < \infty

Plug

x = - \frac{3}{4}

into

- 2 x^{2} - 3 x + 1 : \frac{17}{8}

Maximum (- \frac{3}{4}, \frac{17}{8})

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Frequently Asked Questions (FAQ)

What is the extreme y=-2x^2-3x+1 ?
The extreme y=-2x^2-3x+1 is Maximum(-3/4 , 17/8)