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Popular >

extreme f(x)=sqrt(x^2+25)

Solution

extreme points

f (x) = x^{2} + 25

Solution

Minimum (0, 5)

Solution steps

f^{'} (x) = \frac{x}{x ^{2} + 25}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + 25 : 5

Minimum (0, 5)

Popular Examples

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y = x^{x}, x > 0

extreme f(x)=x^3-4x^2-3x+7 extreme points

f (x) = x^{3} - 4 x^{2} - 3 x + 7

extreme f(x)=x^2+y^2-2y-9 extreme points

f (x) = x^{2} + y^{2} - 2 y - 9

extreme f(x)=-0.4x^2+90x-2000 extreme points

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extreme f(x)=x^3+3x^2+4,-3<= x<= 2 extreme points

f (x) = x^{3} + 3 x^{2} + 4, - 3 \leq x \leq 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(x^2+25) ?
The extreme f(x)=sqrt(x^2+25) is Minimum(0,5)