What is the extreme f(x)=x^3-3x^2-45x+9 ?

The extreme f(x)=x^3-3x^2-45x+9 is Maximum(-3,90),Minimum(5,-166)

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extreme f(x)=x^3-3x^2-45x+9

extreme points

f (x) = x^{3} - 3 x^{2} - 45 x + 9

Maximum (- 3, 90), Minimum (5, - 166)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 45

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 3

into

x^{3} - 3 x^{2} - 45 x + 9 : 90

Maximum (- 3, 90)

Plug

x = 5

into

x^{3} - 3 x^{2} - 45 x + 9 : - 166

Minimum (5, - 166)

Maximum (- 3, 90), Minimum (5, - 166)

f (x) = 4 x^{2} - 2 x

f (x) = (x^{2} - 1) e^{x}

f (x) = \frac{1}{x - 1}

f (x, y) = \frac{1}{3} x^{3} - 3 x^{2} + \frac{y ^{2}}{4} + x y + 13 x - y + 2

\frac{x ^{2}}{x + 1}

What is the extreme f(x)=x^3-3x^2-45x+9 ?
The extreme f(x)=x^3-3x^2-45x+9 is Maximum(-3,90),Minimum(5,-166)