What is the extreme f(x)=x^3-2x^2-4x ?

The extreme f(x)=x^3-2x^2-4x is Maximum(-2/3 , 40/27),Minimum(2,-8)

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extreme f(x)=x^3-2x^2-4x

extreme points

f (x) = x^{3} - 2 x^{2} - 4 x

Maximum (- \frac{2}{3}, \frac{40}{27}), Minimum (2, - 8)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x : \frac{40}{27}

Maximum (- \frac{2}{3}, \frac{40}{27})

Plug

x = 2

into

x^{3} - 2 x^{2} - 4 x : - 8

Minimum (2, - 8)

Maximum (- \frac{2}{3}, \frac{40}{27}), Minimum (2, - 8)

y = \frac{x ^{3} ( 3 x - 8 )}{12}

f (x, y) = x y^{2} - 6 x^{2} - 3 y^{2}

f (x) = e^{3 x} (7 - x)

\frac{( - x ^{2} - 8 x + 20 )}{( x ^{2} - 5 x ) ^{2}}

f (x) = 2 x^{2} + 1

What is the extreme f(x)=x^3-2x^2-4x ?
The extreme f(x)=x^3-2x^2-4x is Maximum(-2/3 , 40/27),Minimum(2,-8)