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Popular >

extreme f(x)=x^4+4x+1

Solution

extreme points

f (x) = x^{4} + 4 x + 1

Solution

Minimum (- 1, - 2)

Solution steps

f^{'} (x) = 4 x^{3} + 4

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{4} + 4 x + 1 : - 2

Minimum (- 1, - 2)

Popular Examples

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extreme f(x)=x^4-8x^3+16x^2 extreme points

f (x) = x^{4} - 8 x^{3} + 16 x^{2}

extreme f(x)=16+4x-x^2,0<= x<= 5 extreme points

f (x) = 16 + 4 x - x^{2}, 0 \leq x \leq 5

extreme f(x)=(x^3)/3-x^2-3x-1 extreme points

f (x) = \frac{x ^{3}}{3} - x^{2} - 3 x - 1

extreme f(x,y)=x^4+y^4-16xy extreme points

f (x, y) = x^{4} + y^{4} - 16 x y

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4+4x+1 ?
The extreme f(x)=x^4+4x+1 is Minimum(-1,-2)