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Popular >

extreme f(x)=x^2+2x+1

Solution

extreme points

f (x) = x^{2} + 2 x + 1

Solution

Minimum (- 1, 0)

Solution steps

f^{'} (x) = 2 x + 2

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x + 1 : 0

Minimum (- 1, 0)

Popular Examples

extreme f(x,y)=(x-1)(y+2)(x+y-2)extreme points

f (x, y) = (x - 1) (y + 2) (x + y - 2)

extreme f(x,y)=(13720)/x+(13720)/y+5xy extreme points

f (x, y) = \frac{13720}{x} + \frac{13720}{y} + 5 x y

extreme f(x)=4x^3-8x extreme points

f (x) = 4 x^{3} - 8 x

extreme f(x)=12x^5+45x^4-360x^3+6 extreme points

f (x) = 12 x^{5} + 45 x^{4} - 360 x^{3} + 6

extreme f(x)=(x^2+3x-1)^{1/3}extreme points

f (x) = (x^{2} + 3 x - 1)^{\frac{1}{3}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+2x+1 ?
The extreme f(x)=x^2+2x+1 is Minimum(-1,0)