What is the extreme f(x)=x^3-x^2-x+4 ?

The extreme f(x)=x^3-x^2-x+4 is Maximum(-1/3 , 113/27),Minimum(1,3)

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extreme f(x)=x^3-x^2-x+4

extreme points

f (x) = x^{3} - x^{2} - x + 4

Maximum (- \frac{1}{3}, \frac{113}{27}), Minimum (1, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 4 : \frac{113}{27}

Maximum (- \frac{1}{3}, \frac{113}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 4 : 3

Minimum (1, 3)

Maximum (- \frac{1}{3}, \frac{113}{27}), Minimum (1, 3)

f (x) = 2 x + \frac{8}{x}

f (x, y) = 3 x^{4} + 3 y^{4} - 2 x y

f (x) = 4 x^{5} - 60 x^{3}

f (x, y) = x^{3} - 3 x y - y^{3}

f (x, y) = (x^{2} + y^{2}) e^{- x}

What is the extreme f(x)=x^3-x^2-x+4 ?
The extreme f(x)=x^3-x^2-x+4 is Maximum(-1/3 , 113/27),Minimum(1,3)