What is the extreme f(x)=14x^3+336x^2 ?

The extreme f(x)=14x^3+336x^2 is Maximum(-16,28672),Minimum(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=14x^3+336x^2

extreme points

f (x) = 14 x^{3} + 336 x^{2}

Maximum (- 16, 28672), Minimum (0, 0)

Solution steps

f^{'} (x) = 42 x^{2} + 672 x

Find intervals:

Increasing

: - \infty < x < - 16,

Decreasing

: - 16 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 16

into

14 x^{3} + 336 x^{2} : 28672

Maximum (- 16, 28672)

Plug

x = 0

into

14 x^{3} + 336 x^{2} : 0

Minimum (0, 0)

Maximum (- 16, 28672), Minimum (0, 0)

f (x) = x^{2} + \frac{14}{x}

f (x) = e^{x} (2 x^{2} + x - 8)

f (x) = x^{\frac{1}{3}} (x - 7)^{2}

f (x) = 4 - 3 x - x^{3}

f (x) = 11 - 5 x + x^{2}

What is the extreme f(x)=14x^3+336x^2 ?
The extreme f(x)=14x^3+336x^2 is Maximum(-16,28672),Minimum(0,0)