en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme y=x^2+6x+5

Solution

extreme points

y = x^{2} + 6 x + 5

Solution

Minimum (- 3, - 4)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

x^{2} + 6 x + 5 : - 4

Minimum (- 3, - 4)

Popular Examples

extreme f(x)=(x^2+3)/(1x-1)extreme points

f (x) = \frac{x ^{2} + 3}{1 x - 1}

extreme f(x)=x^{2/3}(x-7)extreme points

f (x) = x^{\frac{2}{3}} (x - 7)

extreme x^4+x^2-10x+25 extreme points

x^{4} + x^{2} - 10 x + 25

extreme f(x)=2x^3+3x^2-2x-2 extreme points

f (x) = 2 x^{3} + 3 x^{2} - 2 x - 2

extreme f(x,y)=60x+34y-4xy-6x^2-3y^2+5 extreme points

f (x, y) = 60 x + 34 y - 4 x y - 6 x^{2} - 3 y^{2} + 5

Frequently Asked Questions (FAQ)

What is the extreme y=x^2+6x+5 ?
The extreme y=x^2+6x+5 is Minimum(-3,-4)