What is the extreme f(x)=12x+17x^{12/17} ?

The extreme f(x)=12x+17x^{12/17} is Minimum(-1,5),Maximum(0,0)

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extreme f(x)=12x+17x^{12/17}

extreme points

f (x) = 12 x + 17 x^{\frac{12}{17}}

Minimum (- 1, 5), Maximum (0, 0)

Solution steps

f^{'} (x) = 12 + \frac{12}{x ^{\frac{5}{17}}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

12 x + 17 x^{\frac{12}{17}} : 5

Minimum (- 1, 5)

Plug

x = 0

into

12 x + 17 x^{\frac{12}{17}} : 0

Maximum (0, 0)

Minimum (- 1, 5), Maximum (0, 0)

f (x) = x - 4 x

f (x) = x^{2} + \frac{360}{x}, [0, \infty]

f (x) = x^{2} y + x y^{2}

f (x) = x^{2} - 6 x + 11

f (x) = x + \frac{256}{x ^{2}}

What is the extreme f(x)=12x+17x^{12/17} ?
The extreme f(x)=12x+17x^{12/17} is Minimum(-1,5),Maximum(0,0)