What is the extreme (x^2-1)(x^2-9) ?

The extreme (x^2-1)(x^2-9) is Minimum(-sqrt(5),-16),Maximum(0,9),Minimum(sqrt(5),-16)

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extreme (x^2-1)(x^2-9)

extreme points

(x^{2} - 1) (x^{2} - 9)

Minimum (- 5, - 16), Maximum (0, 9), Minimum (5, - 16)

Solution steps

f^{'} (x) = 4 x (x + 5) (x - 5)

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

(x^{2} - 1) (x^{2} - 9) : - 16

Minimum (- 5, - 16)

Plug

x = 0

into

(x^{2} - 1) (x^{2} - 9) : 9

Maximum (0, 9)

Plug

x = 5

into

(x^{2} - 1) (x^{2} - 9) : - 16

Minimum (5, - 16)

Minimum (- 5, - 16), Maximum (0, 9), Minimum (5, - 16)

f (x) = 3 x^{2} + 2 y^{2} - x y - 4 x - 7 y + 12

y = \frac{\frac{25}{32} x ^{3} + 6400}{x}

f (x) = x ∣ x ∣

E (x) = x^{4} - 8 x + 3 x^{2} + x m - 5 - 11

f (x, y) = y^{3} + (6 x^{2}) y - 6 x^{2} - 6 y^{2} + 3

What is the extreme (x^2-1)(x^2-9) ?
The extreme (x^2-1)(x^2-9) is Minimum(-sqrt(5),-16),Maximum(0,9),Minimum(sqrt(5),-16)