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Popular >

extreme f(x)=x^2-8x+15

Solution

extreme points

f (x) = x^{2} - 8 x + 15

Solution

Minimum (4, - 1)

Solution steps

f^{'} (x) = 2 x - 8

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} - 8 x + 15 : - 1

Minimum (4, - 1)

Graph

Popular Examples

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f (x) = 3 x^{4} - 4 x^{3} - 36 x^{2} + 5

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extreme f(x)=-x^4+16x^3-16x+11 extreme points

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f (x) = x^{3} + x^{2} - 2 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-8x+15 ?
The extreme f(x)=x^2-8x+15 is Minimum(4,-1)