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Popular >

extreme f(x)=x^2-7x+12

Solution

extreme points

f (x) = x^{2} - 7 x + 12

Solution

Minimum (\frac{7}{2}, - \frac{1}{4})

Solution steps

f^{'} (x) = 2 x - 7

Find intervals:

Decreasing

: - \infty < x < \frac{7}{2},

Increasing

: \frac{7}{2} < x < \infty

Plug

x = \frac{7}{2}

into

x^{2} - 7 x + 12 : - \frac{1}{4}

Minimum (\frac{7}{2}, - \frac{1}{4})

Graph

Popular Examples

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f (x) = (x - 2)^{\frac{1}{3}}

extreme f(x)=-x^3+x^2-9x+8,-1<= x<= 5 extreme points

f (x) = - x^{3} + x^{2} - 9 x + 8, - 1 \leq x \leq 5

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f (x) = 2 x^{3} - 6 x^{2} - 18 x + 9

extreme f(x)=x^2-1/x extreme points

f (x) = x^{2} - \frac{1}{x}

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f (x) = 2 x^{2} - 2 x^{4}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-7x+12 ?
The extreme f(x)=x^2-7x+12 is Minimum(7/2 ,-1/4)