What is the extreme f(x)=x^3+2x^2-4x+2 ?

The extreme f(x)=x^3+2x^2-4x+2 is Maximum(-2,10),Minimum(2/3 , 14/27)

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extreme f(x)=x^3+2x^2-4x+2

extreme points

f (x) = x^{3} + 2 x^{2} - 4 x + 2

Maximum (- 2, 10), Minimum (\frac{2}{3}, \frac{14}{27})

Solution steps

f^{'} (x) = 3 x^{2} + 4 x - 4

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < \frac{2}{3},

Increasing

: \frac{2}{3} < x < \infty

Plug

x = - 2

into

x^{3} + 2 x^{2} - 4 x + 2 : 10

Maximum (- 2, 10)

Plug

x = \frac{2}{3}

into

x^{3} + 2 x^{2} - 4 x + 2 : \frac{14}{27}

Minimum (\frac{2}{3}, \frac{14}{27})

Maximum (- 2, 10), Minimum (\frac{2}{3}, \frac{14}{27})

\frac{d}{d x} (8 x^{4} - 24 x^{2} + r - 1)

x^{3} - 3 x^{2} - 23 x + 8

6 x^{5} + 33 x^{4} - 30 x^{3} + 100

f (x, y) = x^{2} + y^{2} - 10

f (x) = \frac{( x + 1 )}{x ^{2} + x + 1}

What is the extreme f(x)=x^3+2x^2-4x+2 ?
The extreme f(x)=x^3+2x^2-4x+2 is Maximum(-2,10),Minimum(2/3 , 14/27)