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Popular >

extreme f(x)=(x-2)^5

Solution

extreme points

f (x) = (x - 2)^{5}

Solution

Saddle (2, 0)

Solution steps

f^{'} (x) = 5 (x - 2)^{4}

Find intervals:

Increasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

(x - 2)^{5} : 0

Saddle (2, 0)

Popular Examples

extreme f(x)=-16-7x-x^2 extreme points

f (x) = - 16 - 7 x - x^{2}

extreme f(x,y)=-5x^2-8y^2-2xy+42x+102y extreme points

f (x, y) = - 5 x^{2} - 8 y^{2} - 2 x y + 42 x + 102 y

extreme f(x)=y^3+3x^2y-6x^2-6y^2+2 extreme points

f (x) = y^{3} + 3 x^{2} y - 6 x^{2} - 6 y^{2} + 2

extreme x^2+2xy+2y^2+2x-2y extreme points

x^{2} + 2 x y + 2 y^{2} + 2 x - 2 y

extreme f(x)=t^3-15t^2+72t+8 extreme points

f (x) = t^{3} - 15 t^{2} + 72 t + 8

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-2)^5 ?
The extreme f(x)=(x-2)^5 is Saddle(2,0)